I have made these calculations thanks to the formulas that we have learned in class:
D=10*(m-M+5/5) where M it's the absolute magnitude and m apparent magnitude. M=-3.04 and m=2.87
D=10*(2.87-(-3.04)+5/5)
D=10*(1091/500)
D=152.05pc
I have found that the distance it's approximately of 165 pc this time I have been really close again.