I have made these calculations thanks to the formulas that we have learned in class:

D=10*^{(m-M+5/5)} where M it's the absolute magnitude and m apparent magnitude. M=-3.882 and m=2.942

D=10*^{(2.942-(-3.882)+5/5)}

D=10*^{(1478/625)}

D=231pc

I have found that the distance it's approximately of 160pc this time I have been really far. Probably it's because I have rounded out the numbers.